4(6x^2-3)-[2(5x^2-1)+1]=0

Solution for 4(6x^2-3)-[2(5x^2-1)+1]=0 equation:

Simplifying
4(6x2 + -3) + -1[2(5x2 + -1) + 1] = 0

Reorder the terms:
4(-3 + 6x2) + -1[2(5x2 + -1) + 1] = 0
(-3 * 4 + 6x2 * 4) + -1[2(5x2 + -1) + 1] = 0
(-12 + 24x2) + -1[2(5x2 + -1) + 1] = 0

Reorder the terms:
-12 + 24x2 + -1[2(-1 + 5x2) + 1] = 0
-12 + 24x2 + -1[(-1 * 2 + 5x2 * 2) + 1] = 0
-12 + 24x2 + -1[(-2 + 10x2) + 1] = 0

Reorder the terms:
-12 + 24x2 + -1[-2 + 1 + 10x2] = 0

Combine like terms: -2 + 1 = -1
-12 + 24x2 + -1[-1 + 10x2] = 0
-12 + 24x2 + [-1 * -1 + 10x2 * -1] = 0
-12 + 24x2 + [1 + -10x2] = 0

Reorder the terms:
-12 + 1 + 24x2 + -10x2 = 0

Combine like terms: -12 + 1 = -11
-11 + 24x2 + -10x2 = 0

Combine like terms: 24x2 + -10x2 = 14x2
-11 + 14x2 = 0

Solving
-11 + 14x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 14x2 = 0 + 11

Combine like terms: -11 + 11 = 0
0 + 14x2 = 0 + 11
14x2 = 0 + 11

Combine like terms: 0 + 11 = 11
14x2 = 11

Divide each side by '14'.
x2 = 0.7857142857

Simplifying
x2 = 0.7857142857

Take the square root of each side:
x = {-0.88640526, 0.88640526}